Difference between revisions of "Module:Calendar date/recurring"

From blackwiki
Jump to navigation Jump to search
blackwiki>Howcheng
blackwiki>Howcheng
Line 29: Line 29:
 
dateparts = os.date("*t", date)
 
dateparts = os.date("*t", date)
 
end
 
end
 +
return date
  
 
-- add the correct number of weeks
 
-- add the correct number of weeks
Line 36: Line 37:
 
--end
 
--end
  
local result = os.date("%Y-%m-%d", date)
+
--local result = os.date("%Y-%m-%d", date)
return result
+
--return result
  
 
end
 
end
  
 
return p
 
return p

Revision as of 00:07, 27 March 2019

Documentation for this module may be created at Module:Calendar date/recurring/doc

--[[ 

Calculates the Gregorian date of a recurring holiday that varies year-to-year, but follows the rule "Nth [day of week] of [month]"

  "month" = month number (1 to 12)
  "weeknumber" = number of week (1 to 4, or -1 to mean "last")
  "dayofweek" = number that represents the day of the week, where 1 = Sunday and 7 = Saturday
  "year" = Gregorian calendar year
               
 ]]

require('Module:No globals')

local p = {}

function p.calculate(frame)
	local args = frame.args

	local ONE_DAY = 86400 -- number of seconds in one day
	local year = tonumber(args.year)
	local month = tonumber(args.month)
	local date = os.time{year=year, month=month, day=1}
	local dateparts = os.date("*t", date)

	-- find the first [dayofweek] of this month
	local dayofweek = tonumber(args.dayofweek)
	while not dateparts["wday"] == dayofweek do
		date = date + ONE_DAY
		dateparts = os.date("*t", date)
	end
return date

	-- add the correct number of weeks
	--local weeknumber = tonumber(args.weeknumber)
	--if weeknumber > 1 then
		--date = date + ((weeknumber - 1) * (7 * ONE_DAY))
	--end

	--local result = os.date("%Y-%m-%d", date)
	--return result

end

return p